2^x-1=(1/8)^3x

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Solution for 2^x-1=(1/8)^3x equation: 



2^x-1=(1/8)^3x

We move all terms to the left:

2^x-1-((1/8)^3x)=0



Domain of the equation: 8)^3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2^x-((+1/8)^3x)-1=0

We multiply all the terms by the denominator


2^x*8)^3x)-((-1*8)^3x)+1=0

We add all the numbers together, and all the variables

2^x*8)^3x)-((-8)^3x)+1=0

Wy multiply elements

16x^2-8)^3x)+1=0

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